// checking for explicit member specialization

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 *
 * Licensed to the Apache Software  Foundation (ASF) under one or more
 * contributor  license agreements.  See  the NOTICE  file distributed
 * with  this  work  for  additional information  regarding  copyright
 * ownership.   The ASF  licenses this  file to  you under  the Apache
 * License, Version  2.0 (the  License); you may  not use  this file
 * except in  compliance with the License.   You may obtain  a copy of
 * the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the  License is distributed on an  "AS IS" BASIS,
 * WITHOUT  WARRANTIES OR CONDITIONS  OF ANY  KIND, either  express or
 * implied.   See  the License  for  the  specific language  governing
 * permissions and limitations under the License.
 *
 * Copyright 1999-2007 Rogue Wave Software, Inc.
 * 
 **************************************************************************/

struct A
{
    int i_;

    // no default ctor declared to exercise the compiler's ability
    // distinguish between a declaration of an explicir member
    // specialization and a definition of the same (see below)
    A (int i): i_ (i) { }
};

template <class T>
struct B {

    int foo () { return a.i_; }
    int bar ();

    static A a;
};

// declare explicit specialization of template members
template <> inline int B<int>::foo ();
template <> int B<int>::bar ();

// make sure this is taken as a declaration and not a definition
// as, for example, with SunPro 5.5 (see bug #411)
template <> A B<int>::a;

// define explicit specialization of template members
template <> inline int B<int>::foo () { return 1; }
template <> int B<int>::bar () { return 1; }
template <> A B<int>::a (1);

// define members of the primary template
template <class T> int B<T>::bar () { return foo (); }
template <class T> A B<T>::a (0);

int main ()
{
    B<char> bc;
    bc.foo ();
    bc.bar ();

    B<int> bi;

    int status = 0;

    if (1 != bi.foo ())
        status |= 1;

    if (1 != bi.bar ())
        status |= 2;

    if (1 != bi.a.i_)
        status |= 4;

    return status;
}